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4.9t^2+9t-350=0
a = 4.9; b = 9; c = -350;
Δ = b2-4ac
Δ = 92-4·4.9·(-350)
Δ = 6941
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{6941}=\sqrt{1*6941}=\sqrt{1}*\sqrt{6941}=1\sqrt{6941}$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-1\sqrt{6941}}{2*4.9}=\frac{-9-1\sqrt{6941}}{9.8} $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+1\sqrt{6941}}{2*4.9}=\frac{-9+1\sqrt{6941}}{9.8} $
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